Chapter 6 Applied Instructions Symbol: D ： Device involved in the shift Word n ： Number of bits Word Explanation: 1. The values of the bits in D are shifted by n bits to the right. The vacancies (b15~b15- n +1) resulting from the shift is filled by 0, and the value of b n -1 is transmitted to SM602. 2. The operand n should be within the range between 1 and 16. 3. Generally, the pulse instruction SFRP is used. Example: When X0.0 is ON, the values of b0~b15 in D0 are shifted by 6 bits to the right, and the value of b5 is transmitted to SM602. The values of b10~b15 are cleared to 0 after the shift. The shift of the values of the bits to the right during a scan is illustrated as follows.
b5~b0 → Being carried (The value of b5 is transmitted to SM602.) b15~b6 → b9~b0 0 → b15~b10 b0 b15 ※ Carry flag After the shift b0 b15 Carry flag 0 Being filled by 0 Additional remark: If n is less than 0, or if n is larger than 16, the instruction is not executed, SM0 is ON, and the error code in SR0 is 16#200B. 6-255 API Instruction code Operand Function 1110 SFR P D, n Shifting the values of the bits in the 16-bit registers by n bits to the right Device X Y M S T C HC D L SM SR E PR K 16# “$” DF D n Pulse instruction 16-bit instruction (5 steps) 32-bit instruction AH500 AH500 - 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 0 0 0 0 0 0 1 0 1 0 1 0 1 0 1