Chapter 6 Applied Instructions 3 th 6#20, the co sult is a positive value. If the sign code in S 1 is # sult is a ne e. 4 #20 r 1 ign d during the c sion, as the e . If 16 nversion re gative valu . 16 o 6#30 is ore onver xample below shows. b15 b0 b7 b8 e 2 sign code in S is 1 D, the conversion re S S + D+1 ) 1 ( , D S + 2 S +4 S +3 -1.231 Floating-point number . - 0 2 3 1 1 Ignored 5. 24 characters at most can be contain ed in the string. Example 1: b15 b0 b7 b8 D0 D1 (D11, D10) D2 16#BF9E04C7 D4 -1.234521 Floating-point number D3 D5 - 0 . 2 3 4 1 5 2 1 Ignored Example 2:
6-478 16#20( ) 16 #2D(-) 16#31(1) 16#30(0) 16#32(2) 16#2E (.) 16#31(1) 16#33(3) 16#00 1 6#BF9D9 168 16#20( ) 16#2D(-) 16#31(1) 16#30(0) 16#32(2) 16#2E(.) 16#34(4) 16#33(3) 16#32(2) 16#35(5) 16#00 16#31(1)