Downloaded from https://www.everyspec.com AMCP 70496 Example No. 12 (Cont'd) 6. Compare 4 and si. The technique 8. ,l/it - 1.0424/1.3760 - 0.7572 u' w 2, for doing this is the F distrlbutfm. ut - 0 from steps 3 and 5' Look in the F tables (Tables 2-17) for ; w 2 in the nu- merator and t, a 9 in the denominator. The critical value for ,s-ignificance at the 1% level it given in Table 2-17 and is 8.02. The ratio 0.7572 is much less than the critical value; so we presume that the null hypothesis is true, i.e., all data are random samples from a single popu- lation, there is no real difference due to the levels of the factor.
The actual value of F oorresponding to 0.7572 in 50% (see Tables in Ref. 13). ,Fin :-. , ... i r