F" Downloaded from https://www.everyspec.com AMCP?M6198 EaPIe No. 36 ' Same &a Example No. 35, but suppose that the failure rats is conetant. Estimate the fatire rate and the Cdf at the 2 failure times, The teot was stopped at the second failure. Procedure Ead 1. Calculate the tbtal-test-time. 1. Tw-10 X 2403 hr +9X 888 hr. * State the number of failures. 10hr * 2. Estimate the failure rate. 2. m2/059 x 103 hr) *33. 9/106-hr 3. Use Table 2-8 to get symn- 3. The 5% anid 95% levels are used (95% - 0 metrical 2-sided 90% s-con- -90%). There are 2 failures. Thi factors fidence limits for A. are 0. 18 and 2.4. 4. Calculate the Cdf 11miti at 4. At 2403 hr.:
118h 8 2403~~A 388 hni:388hr upper Cdf - 1 -exp( 81 x 10-1x 2403) Ow 27% lowor Cdf m 1- exp(-6. 1 X10*X 2403) ow 2. 3%. This is less unaertain than in Example No. 35 (due to the use of parameters In this example) but Is still not very good. _____________________________________________________________________________________________________________ ___........... ____ .~~ ~ ~ ~ ~ ~ ~ .. . ....... ...........